11x^2+13x-340=0

Solution for 11x^2+13x-340=0 equation:

11x^2+13x-340=0

a = 11; b = 13; c = -340;
Δ = b2-4ac
Δ = 132-4·11·(-340)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15129}=123$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-123}{2*11}=\frac{-136}{22}
=-6+2/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+123}{2*11}=\frac{110}{22}
=5
$